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单片机“叮咚”门铃设计

作者: 时间:2013-04-02 来源:网络 收藏

6.汇编源程序

T5HZ EQU 30H

T7HZ EQU 31H

T05SA EQU 32H

T05SB EQU 33H

FLAG BIT 00H

STOP BIT 01H

SP1 BIT P3.7

ORG 00H

LJMP START

ORG 0BH

LJMP INT_T0

START: MOV TMOD,#02H

MOV TH0,#06H

MOV TL0,#06H

SETB ET0

SETB EA

NSP: JB SP1,NSP

LCALL DELY10MS

JB SP1,NSP

SETB TR0

MOV T5HZ,#00H

MOV T7HZ,#00H

MOV T05SA,#00H

MOV T05SB,#00H

CLR FLAG

CLR STOP

JNB STOP,$

LJMP NSP

DELY10MS: MOV R6,#20

D1: MOV R7,#248

DJNZ R7,$

DJNZ R6,D1

RET

INT_T0: INC T05SA

MOV A,T05SA

CJNE A,#100,NEXT

MOV T05SA,#00H

INC T05SB

MOV A,T05SB

CJNE A,#20,NEXT

MOV T05SB,#00H

JB FLAG,STP

CPL FLAG

LJMP NEXT

STP: SETB STOP

CLR TR0

LJMP DONE

NEXT: JB FLAG,S5HZ

INC T7HZ

MOV A,T7HZ

CJNE A,#03H,DONE

MOV T7HZ,#00H

CPL P1.0

LJMP DONE

S5HZ: INC T5HZ

MOV A,T5HZ

CJNE A,#04H,DONE

MOV T5HZ,#00H

CPL P1.0

LJMP DONE

DONE: RETI

END

7. C语言源程序

#include AT89X51.H>

unsigned char t5hz;

unsigned char t7hz;

unsigned int tcnt;

bit stop;

bit flag;

void main(void)

{

unsigned char i,j;

TMOD=0x02;

TH0=0x06;

TL0=0x06;

ET0=1;

EA=1;

while(1)

{

if(P3_7==0)

{

for(i=10;i>0;i--)

for(j=248;j>0;j--);

if(P3_7==0)

{

t5hz=0;

t7hz=0;

tcnt=0;

flag=0;

stop=0;

TR0=1;

while(stop==0);

}

}

}

}

void t0(void) interrupt 1 using 0

{

tcnt++;

if(tcnt==2000)

{

tcnt=0;

if(flag==0)

{

flag=~flag;

}

else

{

stop=1;

TR0=0;

}

}

if(flag==0)

{

t7hz++;

if(t7hz==3)

{

t7hz=0;

P1_0=~P1_0;

}

}

else

{

t5hz++;

if(t5hz==4)

{

t5hz=0;

P1_0=~P1_0;

}

}

}


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