新闻中心

EEPW首页>嵌入式系统>设计应用> 单片机拉幕式数码显示技术

单片机拉幕式数码显示技术

作者: 时间:2013-04-02 来源:网络 收藏

NEX6: CJNE A,#07H,NEX7

MOV 36H,#8

MOV 35H,#8

MOV 34H,#8

MOV 33H,#8

MOV 32H,#8

MOV 31H,#8

MOV 30H,#8

LJMP DONE

NEX7: CJNE A,#08H,NEX8

MOV 37H,#8

MOV 36H,#8

MOV 35H,#8

MOV 34H,#8

MOV 33H,#8

MOV 32H,#8

MOV 31H,#8

MOV 30H,#8

LJMP DONE

NEX8: CJNE A,#00H,DONE

MOV 37H,#10

MOV 36H,#10

MOV 35H,#10

MOV 34H,#10

MOV 33H,#10

MOV 32H,#10

MOV 31H,#10

MOV 30H,#10

LL: LJMP DONE

DONE: RETI

TABLE: DB 3FH,06H,5BH,4FH,66H,6DH,7DH,07H,7FH,6FH,00H

END

7. C语言源程序

#include AT89X51.H>

unsigned char code dispcode[]={0x3f,0x06,0x5b,0x4f,

0x66,0x6d,0x7d,0x07,

0x7f,0x6f,0x77,0x7c,

0x39,0x5e,0x79,0x71,0x00};

unsigned char dispbitcode[]={0xf8,0xf9,0xfa,0xfb,

0xfc,0xfd,0xfe,0xff};

unsigned char dispbuf[8]={16,16,16,16,16,16,16,16};

unsigned char dispbitcnt;

unsigned int t02scnt;

unsigned char t5mscnt;

unsigned char u;

unsigned char i;

void main(void)

{

TMOD=0x02;

TH0=0x06;

TL0=0x06;

TR0=1;

ET0=1;

EA=1;

while(1);

}

void t0(void) interrupt 1 using 0

{

t5mscnt++;

if(t5mscnt==4)

{

t5mscnt=0;

P0=dispcode[dispbuf[dispbitcnt]];

P1=dispbitcode[dispbitcnt];

dispbitcnt++;

if(dispbitcnt==8)

{

dispbitcnt=0;

}

}

t02scnt++;

if(t02scnt==1600)

{

t02scnt=0;

u++;

if(u==9)

{

u=0;

}

for(i=0;i8;i++)

{

dispbuf[i]=16;

}

for(i=0;iu;i++)

{

dispbuf[i]=8;

}

}

}


上一页 1 2 3 下一页

评论


相关推荐

技术专区

关闭