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单片机中断实验4

作者: 时间:2016-11-21 来源:网络 收藏
电路图:

程序代码如下:
//交通灯控制程序
#include
unsigned char t0, t1; //定义 全局变量,用来保存延时时间循环次数
//delay0_5s1
//功能:用T1的工作方式1编制0.5s延时程序,假定系统采用12Mhz晶振,定时器1,工作方式1定时50ms,再循环10次即可定时到0.5s
void delay0_5s1 () {
for (t0=0; t0<0x0a; t0++) {
TH1 = 0x3c;
TL1 = 0xb0;
TR1 = 1;
while (!TF1);
TF1=0;
}
}
//delay_t1
//功能:实现0.5s * 延时
//形参:unsigned char t;
// 延时时间为0.5s*t;
void delay_t1 (unsigned char t) {
for (t1=0; t1
delay0_5s1();
}
//int_0
//外部中断0中断函数,紧急情况处理,当cpu响应外部中断0的中断请求时,自动执行该函数,实现两个方向的红灯同时亮10s
void int_0 () interrupt0 {
unsigned char i,j,k,l,m;
i = P1; //保护现场,暂存P1, t0, t1, TH1, TL0;
j = t0;
k = t1;
l = TH1;
m = TL1;
P2 = 0xdb; //两个方向都是红灯
delay_t1 (20); //延时10s
P2 = i;
t0 = j;
t1 = k;
TH1 = 1;
TL1 = m;
}
//int_1
//功能:外部中断1中断函数, 特殊情况处理,当cpu,当cpu响应外部中断1的中断请求时, 自动执行该函数,实现a到放行5s
void int_1 () interrupt 2 {
unsigned char i,j,k,l,m;
EA = 0;
i = P1;
j = t0;
k = t1;
l = TH1;
m = TL1;
EA = 1;
P2 = 0xf3;
delay_t1 (10);
EA = 0;
P2 = i;
t0 = j;
t1 = k;
TH1 = l;
TL1 = m;
EA = 1;
}
void main () {
unsigned char k;
TMOD = 0x10; //T1在工作方式1
EA = 1; //开总中断
EX0 = 1;
IT0 = 1;
EX1 = 1;
IT1 = 1;
while (1) {
P2 = 0xf3;
delay0_5s1();
P2 = 0xfb;
delay0_5s1();
}
P2 = 0xeb;
delay_t1(4);
P2 = 0xde;
delay_t1(110);
for (k=0; k<3; k++) {
P2 = 0xde;
delay0_5s1();
P2 = 0xdf;
delay0_5s1();
}
P2 = 0xdd;
delay_t1(4);
}



关键词:单片机中断实

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