最近研究了一下基于c++的大数乘法算法, 碰到了string类对象与c风格字符串转换问题，有一个问题令我印象深刻，现在没有找到具体原因，记录下来。代码环境是Linux ubuntu，编译器是g++
觉得写得比较好的博客罗列如下:
【转】https://www.cnblogs.com/lifexy/p/8642163.html
1.c_str()
c_str()方法返回一个const char* 类型的指针变量, 该指针变量指向一个字符数组, 字符数组的元素个数是string::length() + 1，最后一个元素为 '\0'
以下为官方说法:
const charT* c_str() const;
Returns: A pointer to the initial element of an array of length size() + 1 whose first size() elements equal the corresponding elements of the string controlled by *this and whose last element is a null character specified by charT().
Requires: The program shall not alter any of the values stored in the array. Nor shall the program treat the returned value as a valid pointer value after any subsequent call to a non-const member function of the class basic_string that designates the same object as this.
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2.在实验中, 不论我在堆上(new)或者在栈上创建一个string类实例, 调用c_str()方法后发现字符数组并没有随着实例的变化而变化，即使实例销毁(delete或者自己析构)，字符数组也没有变化；但是当我改变string的原始内容时, c_str()方法就会有所变化, 记录如下:
当string实例的初始值是"string in stack"时
root@ubuntu:/lianxi/lianxi_c++/string# g++ test_c_str.cpp
root@ubuntu:/lianxi/lianxi_c++/string# ./a.out
=====TEST IN STACK=====
aStr.length() = 15
q[0] = 115
q[1] = 116
q[2] = 114
q[3] = 105
q[4] = 110
q[5] = 103
q[6] = 32
q[7] = 105
q[8] = 110
q[9] = 32
q[10] = 115
q[11] = 116
q[12] = 97
q[13] = 99
q[14] = 107
q[15] = 0
&aStr = 0xbf8df7f0, q = 0x93e4014
aStr1:string in stack
q1:string in stack
aStr2:change in stack
q2:change in stack
q3:change in stack
=====TEST OVER=====
root@ubuntu:/lianxi/lianxi_c++/string#
1 #include
2 #include
3 #include
4 #include
5 #include
6
7 using namespace std;
8
9 /*we use printf in this test instead of cout*/
10 int main(void)
11 {
12 printf("=====TEST IN STACK=====\n");
13 const char* q = NULL;
14 /*code block*/
15 {
16 string aStr("string in stack");
17 printf("aStr.length() = %d\n", aStr.length());//15
18
19 q = aStr.c_str();
20 int j = 0;
21 for(j = 0; j < aStr.length() + 1; j++)
22 {
23 printf("q[%d] = %d\n", j, q[j]);
24 }
25
26 printf("&aStr = %p, q = %p\n", &aStr, q);//address are different
27
28 cout << "aStr1:" << aStr << endl;//string in stack
29 printf("q1:%s\n", q); //string in stack
30
31 aStr = "change in stack";
32 cout << "aStr2:" << aStr << endl;//change in stack
33 printf("q2:%s\n", q); //change in stack
34 }
35
36 printf("q3:%s\n", q); //change in stack
37 printf("=====TEST OVER=====\n");
38 return (0);
39 }
当string实例的初始值是"abcdefg"时:
root@ubuntu:/lianxi/lianxi_c++/string# g++ test_c_str.cpp
root@ubuntu:/lianxi/lianxi_c++/string# ./a.out
=====TEST IN STACK=====
aStr.length() = 7
q[0] = 97
q[1] = 98
q[2] = 99
q[3] = 100
q[4] = 101
q[5] = 102
q[6] = 103
q[7] = 0
&aStr = 0xbfbae130, q = 0x9ba4014
aStr1:abcdefg
q1:abcdefg
aStr2:change in stack
q2:abcdefg
q3:abcdefg
=====TEST OVER=====
root@ubuntu:/lianxi/lianxi_c++/string#
1 #include
2 #include
3 #include
4 #include
5 #include
6
7 using namespace std;
8
9 /*we use printf in this test instead of cout*/
10 int main(void)
11 {
12 printf("=====TEST IN STACK=====\n");
13 const char* q = NULL;
14 /*code block*/
15 {
16 //string aStr("string in stack");
17 string aStr("abcdefg");
18 printf("aStr.length() = %d\n", aStr.length());//15//7
19
20 q = aStr.c_str();
21 int j = 0;
22 for(j = 0; j < aStr.length() + 1; j++)
23 {
24 printf("q[%d] = %d\n", j, q[j]);
25 }
26
27 printf("&aStr = %p, q = %p\n", &aStr, q);//address are different
28
29 cout << "aStr1:" << aStr << endl;//string in stack//abcdefg
30 printf("q1:%s\n", q); //string in stack//abcdefg
31
32 aStr = "change in stack";
33 cout << "aStr2:" << aStr << endl;//change in stack
34 printf("q2:%s\n", q); //change in stack//abcdefg
35 }
36
37 printf("q3:%s\n", q); //change in stack//abcdefg
38 printf("=====TEST OVER=====\n");
39 return (0);
40 }
【注意】:这种机制目前我并不明确, 估计是编译器的某种行为, 但是可以明确看到c_str()方法返回的数组里面有length+1个元素, 且最后一个元素为'\0'
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原文链接：https://blog.csdn.net/liaojunwu/article/details/85269931
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